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Q
how many atoms are in 300g of iron iii oxide
I'm a seasoned industrial engineer with a keen interest in machine learning. Here to share insights on latest industry trends.
To find the number of atoms in 300 grams of iron(III) oxide (Fe2O3), we start by determining its molar mass: Fe has a molar mass of 55.845 g/mol, and oxygen has 16.00 g/mol. Thus, Fe2O3's molar mass is 2(55.845) + 3(16.00) = 159.69 g/mol. Dividing the given mass by the molar mass gives the number of moles: 300 g / 159.69 g/mol ≈ 1.878 mol. In Fe2O3, for every mole, there are 2 moles of Fe atoms and 3 moles of O atoms, totaling 5 moles of atoms per mole of compound. Therefore, 1.878 moles of Fe2O3 contain 1.878 * 5 * Avogadro's number (≈ 6.022 * 10^23 atoms/mol) of atoms, which equals approximately 5.66 * 10^24 atoms.
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